Question

aflati numerele"a"si"b stiind ca:301-(a+b)×2-89=78.a:b=2rest1

Answer 1

301-(a+b)×2-89=78
301-(a+b)×2=78+89
301-(a+b)×2=167
(a+b)×2=301-167
(a+b)×2=134
a+b=134:2
a+b=67

a:b=2 rest1
a =2×b+1
inlocuim pe a in a+b=67
2b+1+b=67
2b+b=67-1
3b=66
b=66:3
b=22

a=67-22
a=45

raspuns
a =45
b =22