Question

aflati numerele naturale care impartite la 37 dau restul egal cu catul .

Answer 1

x:37=c rest r unde c=r
37 este impartitor
impartitorul>restul
37>restul
restul r∈(0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25, 26,27, 28,29,30,31,32,33,34,35,36)
formula pentru aflarea deimpartitului=impartitorul*catul+restul
x=37*0+0=0
x=37*1+1=38
x=37*2+2=76
x=37*3+3=114
x=37*4+4=152
x=37*5+5=190
x=37*6+6=228
x=37*7+7=266
x=37*8+8=304
x=37*9+9=342
x=37*10+10=380
x=37*11+11=418
x=37*12+12=456
x=37*13+13=494
x=37*14+14=532
x=37*15+15=570
x=37*16+16=608
x=37*17+17=646
x=37*18+18=684
x=37*19+19=722
x=37*20+20=760
x=37*21+21=798
x=37*22+22=836
x=37*23+23=874
x=37*24+24=912
x=37*25+25=950
x=37*26+26=988
x=37*27+27=1026
x=37*28+28=1064
x=37*29+29=1102
x=37*30+30=1140
x=37*31+31=1178
x=37*32+32=1216
x=37*33+33=1254
x=37*34+34=1292
x=37*35+35=1330
x=37*36+36=1368
In total 37 de posibilitati.