Question

Aflati numerele x,y,z , stiind ca x/3=y/7=z/11 si x+2y+3z=200

Answer 1

Rezolvarea este urmatoarea:
x/3=y/7=z/11=k⇒x=3k,y=7k,z=11k
x+2y+3z=200
3k+14k+33k=200⇒50k=200⇒k=200:50⇒k=4
x=3k⇒x=3·4⇒x=12
y=7k⇒y=7·4⇒y=28
z=11k⇒z=11·4⇒z=44