Question

aflati tg A, stiind ca sin 60 grade x sin A = cos 30 grade x cos A

Answer 1

Răspuns:

tg A = sinA/cosA

sin60 * sinA = cos30* cosA

$\sqrt{3$/2 * sinA = $\sqrt{3$/2*cosA

sinA = cosA

sinA/cosA = 1⇒   tgA=1

==lucianglont666==

Mult succes!!!