Question

aflati toate numerele naturale x, stiind ca impartind pe 593, 1682 si 24707 la x se obtin resturile 5 ,2 si 11. (metoda de rezolvare pentru clasa a-6-a)

Answer 1

593:x=yrest5
593=xy+5
xy=593-5
xy=588
588/4
147/7
 21/7
   3/3
12imultit 49=599
x=12  ;x=49;;x= 21;x=14;x=4;x=2;x=7;x=3 ;x=6
1682:x=y rest2
1682=xy+2           xy=1680
1680/5
336/3
112/2
56/7
8/2
4/2
2/2
x=2,7,3,5,15,6,36,4,30,45,42,35
24707:x=y rest11
xy=24707-11       xy=24696
24696/2
12348/2
 6174/2
 3087/7
  441/3
  147/7
   21/7
     3/3
x=2,3,7,2,6,,49,,9,343(49x7=343),18,21 441,,294