Question

Aflati toate numerele naturalemai mici decat 500 care,impartite la 12,45 si 18 dau de fiecare data restul 10.

Answer 1

x:12=c1 rest 10
x=M₁₂ +10

x:45=c2 rest 10
x=M₄₅ +10

x:18=c3 rest 10
x=M₁₈ +10

x=[M₁₂; M₄₅ ;M₁₈]+10
x<500

12=2² *3
45=3² *5
18=3² *2

x=3² *2 *5 +10
x=9*10+10
x=90+10
x=100

x=3² *2² *5 +10
x=45*4+10
x=180+10
x=190

x=3³ *2*5+10
x=27*10+10
x=270+10
x=280

x=3² *2*5*4 +10
x=90*4+10
x=360+10
x=370

x=9*2*25+10
x=9*50+10
x=450+10
x=460

x={100;190;280;370;460}