Question

aflati ultima cifră a numărului a=72 la puterea 2003+63 la puterea 2003+ 54 la puterea 2003 + 37 la puterea 2003​

Answer 1

Răspuns:

a=72^2003+63^2003+54^2003+37^2003

u ( 72^2003+63^2003+54^2003+37^2003 )

u ( 72^2003 )= u ( 2^2003 )= u ( 2^4*500+3 )= u ( 2^3 )=8

u ( 63^2003 )= u ( 3^2003 )= u ( 3^4*500+3 )= u ( 3^3 )=7

u ( 54^2003 )= u ( 4^2003 )= u ( 4^2*1001+1 )=4

u ( 37^2003 )= u ( 7^2003 )= u ( 7^4*500+3 )= u ( 7^3 )=3

u ( a )= 8 + 7 + 4 + 3=22