Question

Aflați x aparține N astfel încât a) 3(2x-1)=141 b) 8x+10=6x+18 c) 29-5(x+1)=4 d) 2(3x-1)=3(x+2)+4 e)[37-(x-1)*3] *2 = 14 f) [(x-3)*2+7]:5=15

Answer 1

a) 3(2x-1)=141
3×2x-3×1=14
6x-3=141 => 6x=141+3 => 6x=144 => x=144/6 => x=24

b)8x+10=6x+18
8x-6x=18-10
2x=8 => x=8/2 => x=4

c)29-5(x+1)=4
29-5x+5=4
-5x=4-5-29
-5x=-30
x=-30/-5 => x=6

d) 2(3x-1)=3(x+2)+4
6x-2=3x+6+4
6x-2=3x+10
6x-3x=10+2
3x=12 => x=12/3 => x=4

e) [37-(x-1)×3]×2=14
37-(x-1)×3=14/2
37-(x-1)×3=7
-(x-1)×3=7-37
-(x-1)×3=-30
-(x-1)=-30/3
-(x-1)=-10
-x+1=-10
-x=-11
x=11

f)[(x-3)×2+7]:5=15
2x-3×2+7=15/5
2x-6+7=3
2x=3-7+6
2x=-4+6
2x=2
x=2/2 => x=1