Question

aflati x din relatia
poza mai sus​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Explicație pas cu pas:

$\dfrac{ \sqrt{481 - 27 \cdot \sqrt{9} } }{x} = \dfrac{ \sqrt{55 + 5 \cdot {3}^{2} } }{1 \dfrac{4}{5} \cdot \sqrt{2.(7)} }$

$\dfrac{ \sqrt{481 - 27 \cdot 3} }{x} = \dfrac{ \sqrt{55 + 5 \cdot 9} }{\dfrac{9}{5} \cdot \sqrt{ \dfrac{27 - 2}{9} } }$

$\dfrac{ \sqrt{481 - 81} }{x} = \dfrac{ \sqrt{55 + 45} }{\dfrac{9}{5} \cdot \sqrt{ \dfrac{25}{9} } }$

$\dfrac{ \sqrt{400} }{x} = \dfrac{ \sqrt{100} }{\dfrac{9}{5} \cdot \dfrac{5}{3}}$

$\dfrac{ \sqrt{ {20}^{2} } }{x} = \dfrac{ \sqrt{ {10}^{2} } }{3} \iff \dfrac{20}{x} = \dfrac{10}{3}$

$x = \dfrac{3 \cdot 20}{10} \implies \bf x = 6$