Question

Aflati x,y,z,cunoscand ca {x,y,z} sunt invers proportionale cu {2,3,6} si x-y+z=15
VA ROG AJUTATI-MA

Answer 1

[tex]\{x,y,z\}i.p.\{2,3,6\}=\ \textgreater \ \frac{x}{\frac{1}{2}}=\frac{y}{\frac{1}{3}}=\frac{z}{\frac{1}{6}}=k=\ \textgreater \ \\ =\ \textgreater \ x=\frac{k}{2},y=\frac{k}{3},z=\frac{k}{6}\\ x+y+z=15\\ \frac{k}{2}+\frac{k}{3}+\frac{k}{6}=15|*6\\ 3k+2k+k=90\\ 6k=90=\ \textgreater \ k=15\\ x=\frac{15}{2}\\ y=5\\ z=\frac{5}{2}[/tex]