Question

afllati x din egalitatea 42-{2x+[(x:3+17):5+27]:4}:2=14

Answer 1

42 - {2x+[(x:3+17):5+27]:4}:2=14
{2x+[(x:3+17):5+27]:4}:2 =42-14
{2x+[(x:3+17):5+27]:4}:2= 28
2x+[(x:3+17):5+27]:4=28*2
2x+[(x:3+17):5+27]:4 = 56
2x+[(x:3+17):5+27]=56*4
2x+[(x:3+17):5+27]= 224
(x: 3+17):5+27=224-2x
(x: 3+17):5=224-27 - 2x
(x: 3+17):5= 197-2x
x/15+17/5=197-2x
x/5+2x=197-17/5
x+10x=985-17
11x=968
x=968: 11
x=88