Question

Aici mă ajută cineva ??☹
va rog din suflet ​

Answer 1

Răspuns:

p puterea

2p5*3p7*6p3 = 2p5*3p7*(2*3)p3 = 2p5*3p7*2p3*3p3=2p8*3p10

a=(2p4)p2*(3p5)p2

radical a = 2p4*3p5

3600=2*1800=2p2*900=2p2*3p2*100=2p2*3p2*10p2; radical= 2*3*10=60

1250=2*625=2*5*125=2*5*5*25=2*5*5*5p2=2*5p4; radical= 5p2 radical 2

1125= 3*375= 3*3*125=3p2*5p3; radica= 3*5 radical 5

432= 2*216=2*2*108=2p2*2*54=2p3*2*27=2p4*3p3; radical= 2p2*3 radical 3

8100=81*100=9p2*10p2; radical= 9*10=90

1764=2*2*441=2*23*3*7*7; radical = 2*3*7= 42

A, F, A, F

Explicație pas cu pas: