Question

ajitor va implor foarte mult​

Answer 1

Tinem cont de faptul ca ridicarea la putere are prioritate in fata scaderii si adunarii, deci o facem prima.

a) 5+3^2=5+9=14
b)2^1-2=2-2=0 (orice numar la puterea 1=numarul in sine (x^1=x))
c)10+3*2^2=10+3*4=10+12=22
d)2^4-3^2=16-9=7
e)2+2^2*2=2+4*2=2+8=10
f)50-7^2+9^0 ( orice numar la puterea 0=1) => 50-49+1=1+1=2
g)1^6+1^5-2^0 ( 1 la orice putere=1) =>1+1-2=0
h)(5^2-4^2)*17 =(25-16)*17=9*17=153