Matematică, întrebare adresată de milka564, 8 ani în urmă

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Răspuns de doesntmatter0
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a) \frac{3}{5}  -  \frac{7}{15}  =  \frac{9 - 7}{15}  =  \frac{2}{5}

 \frac{2}{6}  +  \frac{1}{12}  =  \frac{4 + 1}{12}  =  \frac{5}{12}

 \frac{7}{8}  -  \frac{1}{16}  =  \frac{14 - 1}{16}  =  \frac{13}{16}

 \frac{1}{10}  +  \frac{2}{5}  =  \frac{1 + 4}{10}  =  \frac{5}{10}  =  \frac{1}{2}

 \frac{3}{2}  -  \frac{5}{4}  =  \frac{6 - 5}{4}  =  \frac{1}{4}

 \frac{1}{2}  -  \frac{1}{8}  =  \frac{4 - 1}{8}  =  \frac{3}{8}

 \frac{4}{5}  -  \frac{1}{20}  =  \frac{16 - 1}{20}  =  \frac{15}{20}  =  \frac{3}{4}

 \frac{5}{2}  +  \frac{3}{4}  =  \frac{10 + 3}{4}  =  \frac{13}{4}

 \frac{3}{2}  +  \frac{5}{4}  =  \frac{6 - 5}{4}  =  \frac{1}{4}

 \frac{7}{3}  -  \frac{2}{6}  =  \frac{14 - 2}{6}  =  \frac{12}{6}  = 2

b) \frac{5}{3}  \times  \frac{4}{3}  =  \frac{20}{9}

 \frac{5}{6}  \times  \frac{8}{9}  =  \frac{5}{3}  \times  \frac{4}{9}  =  \frac{20}{27}

 \frac{7}{6}  \times  \frac{3}{2}  =  \frac{7}{2}  \times  \frac{1}{2}  =  \frac{7}{4}

 \frac{4}{6}  \times  \frac{5}{3}  =  \frac{2}{3}  \times  \frac{5}{3}  =  \frac{10}{9}

 \frac{9}{2}   \times  \frac{3}{5}  =  \frac{27}{10}

 \frac{7}{4}  \times  \frac{9}{8}  =  \frac{63}{32}

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