Question

Ajutati-ma dau 20 de puncte+coroana

Answer 1

Vezi atasamentul ......

Answer 2

$j)x\cdot(2\frac{7}{3}+1 \frac{1}{2})-3=2\frac{5}{7}\cdot x- \frac{11}{14} \\ \\x\cdot(\frac{7\cdot2+3}{7}+\frac{1\cdot2+1}{2})-3=\frac{2\cdot7+5}{7}\cdot x- \frac{11}{14} \\  \\x\cdot(\frac{17}{7}+\frac{3}{2})-3=\frac{19}{7}\cdot x- \frac{11}{14} \\ \\x\cdot(\frac{17\cdot2+7\cdot3}{14})-3)=\frac{19\cdot2}{14}\cdot x- \frac{11}{14}\\\\\ x\cdot(\frac{34+21}{14}-3=\frac{38x-11}{14} \\ \\ x\cdot55-3\cdot14=38x-11\\ \\55x-38x=3\cdot14-11 \\ \\x=\frac{31}{17}$

$l)\frac{5}{10}\cdot x- \frac{7}{3}=- \frac{4}{9}\cdot x+ \frac{1}{9} \\ \\ 5x\cdot9-7\cdot30=-4\cdot x\cdot10+1\cdot 10\\ \\45x+40x=10+210$

$85x=220\\ \\ x=\frac{220}{85} \\ \\x=\frac{44}{17}$