Question

Ajutati mă la b va rog mult!Va dau coroana

Answer 1

Răspuns:

2$\sqrt{3}$ (x+2) -4$\sqrt{6}$ = 3$\sqrt{3}$ (2x+2$\sqrt{2}$) - 2$\sqrt{3}$x

2$\sqrt{3}$x+ 4$\sqrt{3}$- 4$\sqrt{6}$= 6x$\sqrt{3}$ + 6$\sqrt{6}$ -2$\sqrt{3}$ x

2$\sqrt{3}$ x- 6x$\sqrt{3}$  +2$\sqrt{3}$ = 6$\sqrt{6}$  - 4$\sqrt{3}$+ 4$\sqrt{3}$

-6x$\sqrt{3}$ = 6$\sqrt{6}$   \ (:6)

-x$\sqrt{3}$ = $\sqrt{6}$   \ ( ori (-1)

x$\sqrt{3}$ = - $\sqrt{6}$  

x= -$\sqrt{6}$ /$\sqrt{3}$

x= -1,414