Question

Ajutati-ma va rog frumos ... Este foarte urgent... Va rog frumos V.I si V.II .... multumesc ANTICIPAT!!!!!

Answer 1

poza1

(x-6)/(x+8) x (x+4)/(x-6) = (x+4)/(x+8)

(x+4)/(x-6) : (x-6)/(x+12) = (x+4)/(x-6) x (x-6)/(x+12) = (x+4)/(x+12)

3x-2≠0 ⇒x≠2/3

(x^2-2)/(3x-1) pt x=-3⇒(9 - 2)/(-9-1) = - 7/10

3x/(x-3) x (x+3)/(x+3) = 3x(x+3)/(x^2 - 9)

poza2

3x-2 ≠0 ⇒ x ≠ 2/3

(4+3)/(-4-1)=-7/5

2x/(x+2) x (x-2)/(x-2) = 2x(x-2)/(x^2-4)

(x-3)(x+3)/(x+3)^2 = (x-3)/(x+3)

1/(x+1) + 2/(x+3) = (x+3+2x+2)/(x+2)(x+3) = (3x+5)/(x+2)(x+3)

poza3

(2x+6+x+2)/(x+2)(x+3) = (3x+8)/(x+2)(x+3)

(x+2)/(x+4)

(x-3)/(x-4) : (x-3)/(x-5) = (x-3)/(x-4) x (x-5)/(x-3) = (x-5)/(x-4)

poza4

x≠2/3

(4+3)/(-4-1) = - 7/5

2x/(x+2) x (x-2)/(x-2) = (2x^2-4x)/(x^2-4)

(x-3)(x+3)/(x+3)^2 = (x-3)/(x+3)

s-a facut mai sus

poza5

2/(x+2) + 1/(x+3) = (2x+6+x+2)/(x+2)(x+3) = (3x+8)/(x+2)(x+3)

(x+2)/(x+4)

(x-3)/(x-4) : (x-3)/(x-5) = (x-3)/(x-4) x (x-5)/(x-3)=(x-5)/(x-4)

verifica si tu si corecteaza daca e cazu