Matematică, întrebare adresată de papusicasidaria, 9 ani în urmă

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Răspunsuri la întrebare

Răspuns de samsunggenius200
0
a)  (-\frac{3}{32})*(- \frac{8}{9})*(- \frac{27}{9})=- \frac{1}{4}* \frac{1}{3}*3=- \frac{1}{4}

b) (- \frac{25}{18})* \frac{49}{10}*(- \frac{4}{35})= \frac{5}{9}* \frac{7}{2}* \frac{2}{5}= \frac{1}{9}*7= \frac{7}{9}

c) (-5)*7*(- \frac{3}{5})=7*3=21

d) (- \frac{7}{9})*(-1)* \frac{5}{7}*3= \frac{1}{3}*5= \frac{5}{3}

e) (- \frac{1}{4})*8*(-1)*6*(- \frac{1}{12})=-2* \frac{1}{2}=-1

f)  \frac{7}{3}*(- \frac{19}{36})*(- \frac{15}{14})= \frac{19}{36}* \frac{5}{2}= \frac{19*5}{36*2}= \frac{95}{72}

g) (-2.5)*7.3*(-4)=2.5*7.3*4=10*7.3=73

h) (-2* \frac{1}{4})*(-3* \frac{1}{5})*10=(- \frac{1}{2})*(- \frac{3}{5})*10= \frac{3}{5}*5=3

i)  \frac{-4}{33}* \frac{27}{8}* \frac{-11}{-9}= \frac{1}{3}* \frac{3}{2}= \frac{1}{2}

j)  \frac{-3}{4}*0.2* \frac{1}{-3}*12= \frac{-3}{4}* \frac{1}{5} * \frac{1}{-3}*12= \frac{1}{5}*3= \frac{3}{5}

k) (- \frac{9}{11})*0.99* \frac{50}{-3}=(- \frac{9}{11})* \frac{99}{100} * \frac{50}{-3}=3* \frac{9}{2}= \frac{27}{2}

papusicasidaria: ms
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