Question

ajutatima: i) 0,(3)²; j) 0,(6)²; k) 1,(4)²; l) 2,(15)² vă rog​

Answer 1

Salut!!:)
0,(3)² = ( 3/9 )² = ( 1/3 )² = 1²/3² = (1 × 1)/(3 × 3) = 1/9

0,(6)² = ( 6/9 )³ = ( 2/3 )² = 2²/3² = (2 × 2)/(3 × 3) = 4/9

1,(4)² = ( (14 - 1)/9 )² = ( 13/9 )² = 13²/9² = (13 × 13)/(9 × 9) = 169/81

2,(15)² = ( (215 - 2)/99 )² = ( 213/99 )² = ( 71/33 )² = 71²/33² = (71 × 71)/(33 × 33) = 5041/1089
Sper că te-am ajutat!!

Answer 2

Răspuns:

0,(3)²=(3/9 )²=(1/3)²= 1/3×1/3=1/9

0,(6)²=(6/9)³=(2/3)²2/3×2/3=4/9

1,(4)²=[(14-1)/9]²=(13/9)² =13/9×13/9=169/81

2,(15)²=[(215-2)/99]²=(213/99 )²=(71/33 )²=71/33×71/33=5041/1089