Question

Ajutatima va rog !
5x≤10
2x<9
7x+1≤50
25x+2≤27
12x+4≤20
10x+1≥21
7x-5>44
10x-2<18
3x+2>2x+8
15x+5>10x+25
8x-1≥3x+29

Answer 1

In primul rand "Ajutati-ma,va rog!";

5x<=10; x<=2;x apartine(-infinit,2];
2x<9;x<9/2 ; x apartine (-infinit,9/2);
7x+1<=50;7x<=49;x<=7; x apartine (-infinit,7];
25x+2<=27; 25x<=25;x<=5; x apartine (-infinit,5];
12x+4<=20;12x<=16;x<=3/4; x apartine (-infinit,3/4];
10x+1>=21;10x>=20;x>=2; x apartine [2,+infinit);
7x-5>44;7x>49;x>7; x apartine (7,+infinit);
10x-2<18;10x<20;x<2; x apartine (-infinit,2);
3x+2>2x+8; x>6 ; x apartine (6,+infinit);
15x+5>10x+25; 5x>20;x>4 ;x apartine (4,+infinit);
8x-1>=3x+29; 5x>=30;x>=6; x apartine [6,+infinit);