Question

Ajutatima va rog cu aceasta problema

Answer 1

d) 25 + 3 x (1+0+1)= 25 + 3 x 2=25 + 6 = 31

e)

${5}^{13 - 10} + {4}^{1 + 2} + 9 = {5}^{3} + {4}^{3} + 9 = 125 + 64 + 9 = 198$

f)

$( { {3}^{2} \times 5})^{3}:( {3}^{5} \times 25) = {( {3}^{2}) }^{3} \times {5}^{3} \div ({3}^{5} \times 25) = {3}^{6} \times 125 \div ({3}^{5} \times 25) = 3 \times 125 \div 25 = 3 \times 5 = 15$