Question

ajutatima va rog cu aceste probleme sau macar cu una,multumesc

Answer 1

4.
a)
AB=4
BC=ipotenuza
AD=inaltimea
BD=2
AB²=BD*BC
4²=2*BC
BC=16:2=8 cm
b)  DC=BC-BD=8-2=6 cm

5.AB=5 cm
BD=8 cm
BD intersectat cu AC ={O}
BO=BD=8:2=4 cm
AO=√(AB²-BO²)=√(5²-4²)=√25-16=√9=3 cm
AC=3*2=6 cm
P=5*4=20 cm
Aromb=BD * AC=8*6=24 cm²

6.
a)A=(b*c sin A)/2=10*8 * sin 30⁰/2=40* 1/2=20 cm²
b) AD inaltime BD=BC=8:2=4 cm
AD=√(AB²-BD²)=√(5²-4²)=√25-16=√9=3 cm
A=8x3/2=12 cm²