Question

Ajutatima va rog
Descompuneti in factori
E= (4x+3$) ^{2}$- (x-2[tex]) ^{2} 

Answer 1

$\rm E(x)=(4x+3)^2-(x-2)^2 \\ E(x)=16x^2+24x+9-(x^2-4x+4) \\ E(x)=16x^2+24x+9-x^2+4x-4 \\ E(x)=15x^2+28x+5 \\ \^Il~descompui~pe~28x~in~25x~si~3x: \\ E(x)=15x^2+3x+25x+5 \\ E(x)=3x(5x+1)+5(5x+1) \\ \\ \bold{E(x)=(3x+5)(5x+1)}$