Question

ajutatima varog la ex 7

Answer 1

a) (x+4y)/12 +(2x+5y)/12 =(x+4y+2x+5y)/12 =(3x+9y)/12=3(x+3y)/12=(x+y)/4

b)(a+2b)/2c -(a-4b)/2c =(a+2b -a+4b)/2c =6b/2c =3b/c

c)(a-8)/(a²-25) +13/(a²-25)=(a-8+13)/(a-5)(a+5)=(a+5)/(a-5)(a+5)=1/(a-5)

d)3c/(c²-5c)-(10+c)/(c²-5c)=3c-10+c)/c(c-5)=(2c-10)/c(c-5)=2(c-5)/c(c-5)=2/c

e)y/4+(y-2)/5=(5y+4y-8)/20=(9y+8)/20

f)(a+3)/a²-1/a=(a+3-a)/a²=3/a²

g)( m-n)/m²-(n-m)/mn =(mn-n²-mn+m²)/m²n=(m²-n²)/m²n=(m-n)(m+n)/m²n

h)4a/(3a-6)+3a/(8-4a)=4a/3(a-2)+3a/[-4(a-2)]=(16a-9a)/12(a-2)=7a/12(a-2)

i)4/(c²-9)-2/(c²+3c)=4/(c-3)(c+3)-2/c(c+3)=(4c-2c+6)/c(c-3)(c+3)=
=(2c+6)/c(c-3)(c+3)=2(c+3)/c(c-3)(c+3)=2/c(c-3)

j)3a-12a²/(4a-1)=(12a²-3a-12a²)/(4a-1)=-3a/(4a-1)=3a/(1-4a)

k)6c²/(3c-2) - 2c-5=(6c²-6c²+4c-15c+10)/(3c-2)=(-11c+10)/(3c-2)=
=(10-11c)/(3c-2)