Question

Ajutooooooorrrrrr :))

Answer 1

43.(b/a)^0=1
(b/a)^(-1)=a/b
(b/a)^(-2)=(a/b)^2
adunam
suma=1+a/b+(a/b)^2=1+2/3+4/9=(9+6+4)/9=19/9
a/0.6=b/0.9 rezulta ca a/b=0.6/0.9=2/3
44.a) dam factor comun 1/(2^n) si obtinem 1/(2^n)*(2-1)=1/(2^n)
b)aici sper ca ai invatat formula progresiei geometrice, daca nu, lasa un comentariu si rezolv altfel
paranteza=(2^9-1)/(2^10)
suma=1/2-paranteza (aducem la acelasi numitor) =(2^9-2^9+1)/(2^10)=1/(2^10)