Question

Ajutoooor!!Urgent!!!​

Answer 1

${ \cos(x) }^{2} + { \sin(x) }^{2} = 1$

$\cos(x) = - \frac{3}{5} = > { \cos(x) }^{2} = \frac{9}{25}$

$= > { \sin(x) }^{2} = 1 - { \cos(x) }^{2}$

$\sin(x) = \sqrt{ \frac{25 - 9}{25} } = \sqrt{ \frac{16}{25} } = | \frac{4}{5} |$

$\sin(x) = - \frac{4}{5}$

$\sin(2x) =2 \sin(x) \cos(x) = 2 \times - \frac{4}{5} \times - \frac{3}{5} = \frac{24}{25}$