Question

Ajutooor ! Dau coroană !

Answer 1

In prima relatie inmultesti mezii cu extremii.
$\frac{x + y}{2x + 3y} = \frac{8}{19} \\ = > 19( x+ y) = 8(2x + 3 y) \\ 19x + 19y = 16x + 24y \\ 19x - 16x = 24y - 19y \\ 3x = 5y \\ = > \frac{x}{y} = \frac{5}{3}$

Answer 2

[tex]\it \dfrac{x+y}{2x+3y} = \dfrac{8}{19} \stackrel{derivare}{\Longrightarrow} \dfrac{x+y}{2x+3y-x-y} =\dfrac{8}{19-8} \Rightarrow \dfrac{x+y}{x+2y} = \dfrac{8}{11} \Rightarrow \\ \\ \\ \stackrel{derivare}{\Longrightarrow} \dfrac{x+y}{x+2y-x-y} =\dfrac{8}{11-8} \Rightarrow \dfrac{x+y}{y} = \dfrac{8}{3} \Rightarrow \dfrac{x}{y} +\dfrac{y}{y} = \dfrac{8}{3}\Rightarrow \\ \\ \\ \Rightarrow \dfrac{x}{y} +1 = \dfrac{8}{3} \Rightarrow \dfrac{x}{y} = \dfrac{8}{3}-1 \Rightarrow \dfrac{x}{y} = \dfrac{5}{3}[/tex]