Question

Ajutooor!!!!! DAU COROANAAA

Answer 1

[tex]5* \frac{x!}{(x-3)!*3!}= \frac{(x+2)!}{4!*(x-2)!} \\ \frac{5(x-2)(x-1)x}{6} = \frac{(x-1)x(x+1)(x+2)}{24} \\ 20(x-2)=x(x+1)(x+2) \\ 20x-40= x^{3} +3 x^{2} +2x \\ x ^{3} +3 x^{2} -18x+40=0[/tex]
Si acum calculezi ecuatia. 
Succes!