Question

Ajutooor va rog e pentru maine ​

Answer 1

a.x^2=11+5 =>x^2=16 => x=-4 sau x=4

b. -3x^2=1,2-4=> -3x^2=-2,8=>x^2=28/30 => x=-(14·radical din 15)/15 sau x= (14·radical din 15)/15

c. x^2+5/4x^2=0 =>x=0

d. x€ mulț. vidă

e. x^2=9 => x=-radical din 3 sau x=radical din 3

f. x(x·radical din 5 -5)=0 => x=0 su x= radical din 5

Answer 2

Explicație pas cu pas:

${x}^{2} - 5 = 11 \iff {x}^{2} = 16 \\ {x}^{2} = {4}^{2} \implies x = \pm4$

$- 3{x}^{2} + 4 = 1.2 \iff - 3{x}^{2} = 1.2 - 4 \\ - 3{x}^{2} = - 2.8 \iff {x}^{2} = \dfrac{^{75)} 2.8}{3} \\{x}^{2} = \dfrac{210}{225} \implies x = \pm\dfrac{\sqrt{210} }{15}$

$- \dfrac{5}{4} {x}^{2} = {x}^{2} \iff {x}^{2} + \dfrac{5}{4} {x}^{2} = 0 \\ \Big( 1 + \dfrac{5}{4}\Big) {x}^{2} = 0 \\ {x}^{2} = 0 \implies x = 0$

${(x + 3)}^{2} = - 2 \\ {(x + 3)}^{2} \geqslant 0 \\ \implies x \in \O$

$\sqrt{3} {x}^{2} - \sqrt{27} = 0 \iff \sqrt{3} {x}^{2} - 3\sqrt{3} = 0 \\ \sqrt{3}({x}^{2} - 3) = 0 \iff {x}^{2} - 3 = 0 \\ {x}^{2} = 3 \implies x = \pm \sqrt{3}$

$\sqrt{5} {x}^{2} - 5x = 0 \\ x \sqrt{5} (x - \sqrt{5} ) = 0 \\ \bf x = 0 \\ x - \sqrt{5} = 0 \implies \bf x = \sqrt{5}$