Question

AJUTOR !!
c la puterea a58a : c la puterea a39a : c la puterea a9a

( semnul ":" = impartit )

Answer 1

$c^5^8:c^3^9:c^9=c^{58-39-9}=c^1^0$

Answer 2

$Rezolvare: c^{58}: c^{39}:c ^{9}= c^{58-39-9} \to \boxed{c^{10} }$