Question

Ajutor. Dau coroana ​

Answer 1

$\bf{ \frac{ - 4}{2x + 1 } \geqslant 0 < = > - \frac{4}{2x + 1} \geqslant 0 }$

$\bf{ \frac{1}{2x + 1} \leqslant 0}$

$\bf{2x + 1 < 0 \: \: < = > \: \: 2x < - 1}$

$\bf{x < - \frac{1}{2} \Rightarrow \: x \in ( - infinit , - \frac{1}{2}) }$