Question

Ajutor ex.1 de jos dau coroniță

Answer 1

Exercitiul 1) de jos:

$\displaystyle\\ \frac{x}{y} =\frac{2}{3}~~\Longrightarrow~~x = \frac{2y}{3}\\\\ \left(\frac{33x-22y}{2017}\right)^{2017} =\left(\frac{33\cdot\dfrac{2y}{3}-22y} {2017}\right)^{2017} = \\\\\\ =\left(\frac{11 \cdot 2y -22y}{2017}\right)^{2017} =\left(\frac{22y -22y}{2017}\right)^{2017} =\left(\frac{0}{2017}\right)^{2017} =\boxed{\bf 0}$