Question

Ajutor ex.3 a) si b)

Answer 1

3a)

$\it \dfrac{\ 690^{(10}}{5400} =\dfrac{\ 69^{(3}}{540} = \dfrac{23}{180}$

b)

[tex]\it p\%\ din 690=111 \Rightarrow \dfrac{p}{100}\cdot690=111 \Rightarrow p\cdot\dfrac{690}{100} =111 \Rightarrow \\ \\ \\ \Rightarrow p=111\cdot\dfrac{10}{69} = \dfrac{370}{23} \approx 16\%[/tex]