Question

Ajutor!!!
Incepeti cu primele, va rog!

Answer 1

1.
a)2ay/3x
b)-9bc²
c)3a³/4xy²
d)-1/3xyz
e)√5x/y

2.
a)x(x-2)/(x-2)=x
b)x(y+1)/y(y+1)=x/y
c)4(2x-1)/8x(2x-1)=1/2x
d)9(a-1)(a+1)/3(a+1)=3(a-1)

3.
a)12a(a²+2ab+b²)/6(a+b)=2a(a+b)²/(a+b)=2a(a+b)
b)(2a+3)²/(2a+3)(2a-3)=(2a+3)/(2a-3)
c)x²(x-2)/x(x-2)²=x/(x-2)
d)[b(a+x)+y(a+x)]/a(a+x)=(a+x)(b+y)/a(a+x)=(b+y)/a
e)(x+y+z)²/[(y+z)²-x²]=(x+y+z)²/(y+z+x)(y+z-x)=(x+y+z)/(y+z-x)
f)[(a+b)(a²-ab+b²)+3ab(a+b)]/a(a+b)²=(a+b)³/a(a+b)²=(a+b)/a
g)(x+y)(x²-xy+y²)/(x²-2xy+y²+xy)=(x+y)(x²-xy+y²)/(x²-xy+y²)=x+y

4.
a)(x-5)(x+5)/(x-5)²=(x+5)/(x-5)
b)(2x-1)²/(2x+1)(2x-1)=(2x-1)/(2x+1)
c)(√5x-3)(√5x+3)/(√5x+3)=√5x-3
d)(x-1)(x-5)/(x-1)(x-6)=(x-5)/(x-6)
e)(x-2)(x-6)/(x-2)(x-3)=(x-6)/(x-3)

5.
Nu mai am timp... Scuze, unii mai trebuie sa si munceasca...

6.
Se aduc la numitor comun, apoi se aduna sau se scad.