Question

ajutor la trigonometrie

Answer 1

Explicație pas cu pas:

a)

$\sin(x) = \frac{1}{2} = >$

$x= \frac{\pi}{6} + 2\pi \: n \\ x = \frac{5\pi}{6} + 2\pi \: n$

=>

$x = \frac{\pi}{6} ;x = \frac{5\pi}{6} ; \\ x = \frac{13\pi}{6} ;x = \frac{17\pi}{6}$

b)

$\cos(2x) = - \frac{1}{2}$

$2x = \frac{2\pi}{3} + 2\pi \: n = > x = \frac{\pi}{3} + \pi \: n$

$2x = \frac{4\pi}{3} + 2\pi \: n = > x = \frac{2\pi}{3} + \pi \: n$

=>

$x = \frac{\pi}{3} ;x = \frac{2\pi}{3} ;x = \frac{4\pi}{3} ; \\ x = \frac{5\pi}{3} ;x = \frac{7\pi}{3} ;x = \frac{8\pi}{3}$

Answer 2

Răspuns:

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