Question

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Answer 1

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Answer 2

$1.\\ \\ a) (-\frac{3}{8})+(+\frac{1}{8})=\frac{-3+1}{8}=\frac{-2}{8}=-\frac{1}{4}$

$b) =\frac{-5+2}{9}=\frac{-3}{9}=-\frac{1}{3}$

$c) =\frac{-7-5}{12}=\frac{-12}{12}=-1$

$d) \frac{1}{2}+(-\frac{2}{3}=\frac{3-4}{6}=-\frac{1}{6}$

$e) =\frac{-3\cdot6+4}{24}=\frac{-18+4}{24}=-\frac{7}{12}$

$f) =\frac{-3\cdot5+3}{10}=-\frac{7}{10}$

$g) (-\frac{5}{6})+(+\frac{1}{2})=\frac{-5+3}{6}=\frac{-2}{6}=-\frac{1}{2}$

$h) (-\frac{5}{8})+(+\frac{-3\cdot2}{8})=\frac{-5-6}{8}=\frac{-11}{8}$

$i) (-\frac{4}{7})+(+\frac{3}{14})=\frac{-8+3}{14}=\frac{-5}{14}$

$j)-\frac{5}{7\cdot3} +\frac{9}{2\cdot7} =\frac{-5\cdot2+9\cdot3}{42}=\frac{-10+27}{42}=\frac{17}{42}$