Matematică, întrebare adresată de lorenanicoleta4, 8 ani în urmă

Ajutor pentru aceste 2 ex:
1.Exprima in grame:
1 kg,4kg,1/2 kg,1 kg si 3/4 kg si 3 kg si 1/2 kg.Trebuie si operatiile cum am ajuns la rezultat.
2.Calculeaza:(si aici operatiile)
a.18 g+36 dg=?dg
30 dg+72g=?g
49 kg-210 dag=? hg
67 hg-100 dg=? dag
b.8×50cg+6×250dg=? g
20000g:4-20×1500 dg=? hg
9 t+[500q-(500kg-5×800 hg)×9]=? q
am nevoie urgent!!
dau coroana!!

Răspunsuri la întrebare

Răspuns de Utilizator anonim
1
1.
1kg=1000g
4kg=4000
1/2kg=500g
1kg si 3/4kg=1750g
3kg si 1/2kg=3500g
2.
a)
18g=180dg
180dg+36dg=216dg

30dg=3g
3g+72g=75g

49kg=490hg
210dag=21hg
490hg-21hg=489hg

67hg=670dag
100dg=1dag
670dag-1dag=99dag
b)
8x50cg+6x250dg=?g
50cg=0,5g
250dg=25g
8x0.5g+6x25g=?g
4g+150g=154g

20000g:4-20x1500dg=?h
20000g=200hg
1500dg=1,5hg
200hg:4-20x1,5hg
50hg-30hg=20hg

9t+[500q-(500kg-5x800hg)x9]=?q
9t=90q
500kg=5q
800hg=0.8q
90q+[500q-(5q-5x0.8q)x9]=?q
90q+[500q-(5q-4q)x9]=?q
90q+(500q-1qx9)=?q
90q+491q=581q

lorenanicoleta4: am nevoie si de cum le-ai facut ca sa ajungi la rezultat
elakissup3bs9j: ai mancat din cifre
elakissup3bs9j: 670-1 nu e 99
Răspuns de elakissup3bs9j
3
1) 1kg=1x1000=1000g
4kg=4x1000=4000g
1/2kg=1:2=0,5kg=0,5x1000=500g
1kg=1x1000=1000g
3/4kg=3:4=0,75kg=0,75x1000=750g
1000g+750g=1750g
3kg=3x1000=3000g
1/2kg=1:2=0,5kg=0,5x1000=500g
3000g+500g=3500g

2)a)18g+36dg=18x10+36=180+36=216dg
30dg+72g=30:10+72=3+72=75g
49kg-210dag=49x10-210:10=490-21=469hg
67hg-100dg=67x10-100:100=670-1=669dag

B)8x50cg+6x250dg=8x50:100+6x250:10=400:100+1500:10=4+150=154g
20000g:4-20x1500dg=
=20000:100:4-20x1500:1000=200:4-20x1,5=50-30=20hg

9t+[500q-(500kg-5x800hg)x9]=9x10+[500-(500:100-4000:1000)x9]=90+[500-(5-4)x9]=90+(500-1x9)=90+491=581q
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