Question

ajutor plz repedeewwwe ​

Answer 1

a)

$(25^{4})^{3} : (4^{2} + 3^{2})^{11} - (0^{2010} + 1^{2012} + 2013^{0}) =\\= 25^{12} : (16+9)^{11} - (0 +1 +1) =\\= 25^{12} : 25^{11} - 2 =\\= 25 - 2 =\\= 23$

b)

$[123 + 2^{7} * 2^{2} + 2^{67} : 2^{27}] : [123 + 2^{14} : 2^{5} + (2^{5})^{8}]=\\ = [ 123 + 2^{9} + 2^{40}] : [123 + 2^{9} + 2^{40}] =\\ = 1$

c)

$(2^{8} + 9^{2} + 5^{6} + 36^{2}): (0^{6} + 4^{4} + 3^{4} + 25^{3} + 6^{4}) =\\= (2^{8} + 81 + 5^{6} + 36^{2}) : (0+4^{4} + 81 + 25^{3} + 6^{4})=\\ = (2^{8} + 81 + 5^{6} + 36^{2}) : (4^{4} + 81 + 25^{3} + 6^{4})=\\\\= \frac{2^{8}+81+5^{6} + 36^{2} }{4^{4}+81+25^{3} + 6^{4} }=\\\\ = \frac{256+81+15 625+ 1296}{256+81+15625+1296} =\\\\\= \frac{17258}{17258} =\\\\= 1$

* Sper că te-am ajutat! *