Question

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Answer 1

Răspuns:

3.∆ABC(<A=90°)AB=12cm;BC=20cm

T.P. AC=√20²-12²=√400-144=√256=16cm

sinB=AC/BC =16/20=4/5

cosB=AB/BC =12/20=3/5

tgC=AB/AC=12/16=3/4

ctgC=AC/AB=16/12=4/3

4..∆ABC(<A=90°)AC=20cm;AB=15cm

T.P. BC=√20²+15²=25cm

sinB=AC/BC=20/25=4/5

cosB=AB/BC=15/25=3/5

tgC=AB/AC=15/20=3/4

ctgC=AC/AB=20/15=4/3

5..∆ABC(<A=90°)AB=2√3cm;sinC=2/3=AB/BC

BC=3AB/2=3×2√3/2=3√3cm

T.P. AC=√BC²-AB²=√27-12=√15

sinB=AC/BC=√15/3√3=3√5

cosB=AB/BC=2√3/3√3=2/3

tgC=AB/AC=2√3/√15=2√5/5

ctgC=AC/AB=√15/2√3=√5/2

6..∆ABC(<A=90°)