Question

Ajutor rr!ggfufffgggggggftfffff ggg

Answer 1

Răspuns:

$E(x)=\frac{2x^{2}-18}{x^{2}-6x+9}:\frac{10(x-3)}{5x+15} =\frac{2(x^{2}-3^{2})}{(x+3)^{2}}:\frac{10(x-3)}{5(x+3)}=\frac{2(x-3)}{x+3}*\frac{5(x+3)}{10(x-3)}=\frac{10}{10} =1$

Explicație pas cu pas: