Question

ajutor si aici :)) plsss ×_×

Answer 1

$\displaystyle 1).(-275:25+3) \cdot (-2)=(-11+3) \cdot (-2)=(-8) \cdot (-2)=16 \\ 2).\left[ \frac{1}{3} \cdot \left(10- \frac{1}{4} \right)-3 \frac{2}{5} \right]: \left(2- \frac{4}{5} \right)=\\=\left(\frac{1}{3}\cdot \frac{40-1}{4} }-\frac{5 \cdot 3+2}{5} \right]: \frac{10-4}{5}=\left( \frac{1}{3} \cdot \frac{39}{4} - \frac{17}{5}\right): \frac{6}{5}=\\=\left(\frac{13}{4}-\frac{17}{5}\right):\frac{6}{5}=\frac{65-68}{20}:\frac{6}{5}=\left(-\frac{3}{20} \right) \cdot \frac{5}{6}=-\frac{15}{120}=-\frac{1}{8}$
$\displaystyle 3). \frac{3x+2}{10} + \frac{x-7}{2} = \frac{4x-1}{3} +3x \\ 3(3x+2)+15(x-7)=10(4x-1)+30 \cdot 3x \\ 9x+6+15x-105=40x-10+90x \\ 9x+15x-40x-90x=-10-6+105 \\ -106x=89 \Rightarrow x=- \frac{89}{106}$