Question

Ajutor urgent

Radical din 3 -3radical12+4radical27-5radical48+3radical75

Answer 1

$\sqrt{3} -3 \sqrt{12} +4 \sqrt{27} -5 \sqrt{48} +3 \sqrt{75} = \\ = \sqrt{3} -3 \cdot 2 \sqrt{3} +4 \cdot 3 \sqrt{3} -5 \cdot 4 \sqrt{3} +3 \cdot 5 \sqrt{3} = \\ = \sqrt{3} -6 \sqrt{3} +12 \sqrt{3} -20 \sqrt{3} +15 \sqrt{3} =2 \sqrt{3}$