Question

............ajutor va rog ​

Answer 1

$f(1) = 3 > > a + b + c = 3 \\ f( - 1) = 7 > > a - b + c = 7 \\ f(0) = 1 > > c = 1$

$\binom{a + b + 1 = 3}{a - b + 1 = 7} \\ \binom{a + b = 2}{a - b = 6} \\ 2a = 8 > > a = 4 \\ b = 2 - a = 2 - 4 = - 2$

$a = 4.....b = - 2.....c = 1 \\ f(x) = {ax}^{2} + bx + c \\ f(x) = {4x}^{2} - 2x + 1$