ajutor va rog. dau coroana si ce vreti dar am nevoie repede
Răspunsuri la întrebare
1.
FeO oxid feros
Fe2O3 oxid feric
Fe3O4 oxid fero-feric
SO2 dioxid de sulf
SO3 trioxid de sulf
2.
CO2 + H2O⇄H2CO3
CO2 + Ca(OH)2 =CaCO3 + H2O
Na2O + H2O=2NaOH
CuO + 2HCl= CuCl2 +H2O
3. COMP. PROC. A P2O3
MP2O3=2.31 + 3.16=110 -------> 110g/moli
110gP2O3-----------62g P-----------48g O
100g---------------------x--------------------y
x=100.62 : 110=56,36 % P
y=100. 48 : 110=43,63 % O
4.
-se afla md sol. de H2SO4
md=c.ms :100
md=49 .200 : 100=98 g H2SO4
xg 98g
SO3 + H2O = H2SO4
18g 98g
x=18 .98 : 98= 18 g H2O
Al doilea test
1.
Cu2O oxid cupros
CuO oxid cupric
CO monoxid de carbon
CO2 dioxid de carbon
2.
CaO + H2O=Ca(OH)2
CO2 + 2NaOH=Na2CO3 + H2O
SO2 + H2O=H2SO3
CuO + H2SO4=CuSO4 + H2O
3.
Comp. proc . a SO3
MSO3=32 + 3 .16=80-------> 80g/moli
80g SO3---------32 g S----------48 g O
100 gSO3----------x-------------------y
x=100.32 :80=40% S
y=100.48 : 80=60% O
4.
- se afla md sol. de NaOH
md= c. ms : 100
md=40.200 : 100=80 g NaOH
xg 80g
Na2O + H2O= 2NaOH
18g 2.40g
x=18 .80 : 2 .40=18 g H2O
MH2SO4=2+32+ 4.16=98------>98g/moli
MNaOH=23+16 + 1=40------> 40g/moli
MH2O=2+16=18--------> 18g/moli