Question

ajutor.. va rog , este urgent​

Answer 1

Răspuns:

6

Explicație pas cu pas:

$n=(\frac{3\sqrt{2}-2\sqrt{3}}{\sqrt{6} }+\sqrt{8})*\sqrt{12}-\frac{\sqrt{1+2+...+48} }{7}=\\=(\frac{(3\sqrt{2}-2\sqrt{3})*\sqrt{6}}{(\sqrt{6})^2}+\sqrt{4*2})*\sqrt{4*3}-\frac{\sqrt{(1+48)*48:2} }{7}=\\=(\frac{3\sqrt{12}-2\sqrt{18}}{6}+2\sqrt{2})*2\sqrt{3}-\frac{\sqrt{49*24}}{7}=\\=(\frac{3*\sqrt{4*3}-2\sqrt{9*2}}{6}+2\sqrt{2})*2\sqrt{3}-\frac{7\sqrt{4*6}}{7}=\\=(\frac{6\sqrt{3}-6\sqrt{2}}{6}+2\sqrt{2})*2\sqrt{3}-2\sqrt{6}=(\frac{6(\sqrt{3}-\sqrt{2})}{6}+2\sqrt{2})*2\sqrt{3}-2\sqrt{6}=$

=(√3-√2+2√2)·2√3-2√6=(√3+√2)·2√3-2√6=2·(√3)²+2√2·√3-2√6=2·3+2√6-2√6=6

Deci, n=6