Question

Ajutor va rog frumos ​

Answer 1

Răspuns:

Explicație pas cu pas:

problema3

bm/mc=1/4=>mc=4 bm

bm+mc=bc

bm+4bm=10

5bm=10=>bm=10:5

bm=2

mc=2 ori 4

mc=8

in Δdcb: ∡c=90°

teorema lui pitagora

dc²+bc²=db²

20²+10²=db²

400+100=db²

500=db²=> db=√500=> db=10√5

daca mn║dc=> nb/bd=bm/bc=> nm/10√5= 2/10=> nm=2 ori 10√2/10=>nm= 2√5

dn=10√5-2√5=> dn=8√5

bm/bc= mn/dc

2/10=mn/20=> mn=  20 ori 2/10=> mn= 4

aria mnpc= mn ori mc

aria mnpc= 4 ori 8

aria mnpc=32 cm²

perimetrul mnpc =2 ori (mn+mc)

perimetrul mnpc= 2ori (4+8)

perimetrul mnpc=2 iru 12=24 cm

problema 4

nu stiu exact