Question

Ajutor!!!!√x+√9-x=3.

Answer 1

[tex]\text{Punem conditii:}\\ x\geq 0\ si\ x\leq 9\Rightarrow x\in [0,9]\\ \sqrt{x}+\sqrt{9-x}=3|()^2\\ x+9-x+2\sqrt{x(9-x)}=9\\ 2\sqrt{x(9-x)}=0|:2\\ \sqrt{x(9-x)}=0|()^2\\ x(9-x)=0\Rightarrow x\in \{0,9\} [/tex]