Question

ajutorr ex 14 dau coroana​

Answer 1

Răspuns:

Explicație pas cu pas:

U(a)

3²⁰¹⁹

U(3¹)=3

U(3²)=9

U(3³)=...7

U(3⁴)...1

U(3⁵)....3

2019:4= 504 rest 3 ....U (3²⁰¹⁹)= 7 ( ultima cifra)

-

5 ridicat la orice putere are U =5 ( ultima cifra)

-

1 ridicat la orice putere are U = 1

-

a= 7+5+1=13

U(a) =3

-

U(b)

2²⁰¹⁹

U(2¹)=2

U(2²)=4

U(2³)=8

U(2⁴)=...6

U(2⁵)= ...2

2019:4= 504 rest 3→ U(2²⁰¹⁹)= 8

-

6²⁰²⁰

6 ridicat la orice putere are ultima cifra U( 6) = 6

-

2019⁰

Orice nr ridicat la puterea 0 are ultima cifra U ( 2019⁰)=1

8+6+1=15 U ( b)→ (ultima cifra =5

-

-

U(c)

U(4¹)=4

U(4²)=...6

U(4³)=...4

2019:3=673 rest 0 →U( 4²⁰¹⁹)=6

-

7²⁰²⁰

U(7¹)=7

U(7²)=...9

U(7³)=...3

U(7⁴)=...1

U(7⁵)= ..7

2020:4=504 rest 0 → ultima cifra = 1

-

8²⁰²¹

U( 8¹)=8

U(8²)=...4

U(8³)=...2

U(8⁴)= ...6

U(8⁵)=...8

2021:4= 505 rest 1→ultima cifra= 8

-

9²⁰²⁰

U(9¹)=9

U(9²)= ...1

U(9³)=....9

2022:2= 1011 rest 0 → ultima cifra= 1

6+1+8+1= 16 → ultima cifra= 6