Question

Ajutorrr ex 1!!!! VA ROG MULTTT!!!!!

Answer 1

$(- \frac{1}{125}):0,008 +0,(7)+[0,(3)]^{2}= \\ = (-\frac{1}{125}): \frac{8}{1000}+ \frac{7}{9}+( \frac{1}{3})^{2} = \\ = (-\frac{1}{125}): \frac{1}{125} + \frac{7}{9}+ \frac{1}{9}= \\ =-1+ \frac{8}{9}= \\ =-\frac{1}{9} .$

Answer 2

$(-\frac{1}{125}):0,008+0,(7)+0,(3)^2=(-\frac{1}{125}):\frac{8}{1000} + \frac{7}{9}+(\frac{3}{9})^2 = \\ = (-\frac{1}{125})*\frac{1000}{8}+\frac{7}{9}+\frac{1}{9}=(-1)+\frac{8}{9}=\frac{-9+8}{9}= \\ = -\frac{1}{9}$
Success!