Question

Ajutorrrrr! E urgent :''vvv

Answer 1

Explicație pas cu pas:

1.

f : R -> R

f(x)=x⁴

f(-x)=(-x)⁴=x⁴

f(x)=f(-x) => f(x) este pară

f(-2)+f(-1/2)+f(2)-1

=(-2)⁴+(-1)⁴+2⁴-1

=2⁴+1+2⁴-1

=2⁴+2⁴

=2×2⁴

=2¹⁺⁴

=2⁵

=32

2. f:R -> R

f(x)=xⁿ , n∈ ℕ

f(3)=27=3³

f(2²)-f(2)=f(4)-f(2)=

=4³-2³=64-8=56

3.

f, g : R -> R

f(x)=x³

g(x)=x⁶

g(1)=1⁶=1

f(g(1))=f(1)=1³=1

f(2)=2³=8

g(f(2))=g(8)=8⁶

f(g(1))+g(f(2))=1+8⁶=1+262144=262145

g(∛2)=(∛2)⁶=∛(2³×2³)=2×2=4

f(g(∛2))=f(4)=4³=64

f(-∛3)=(-∛3)³=-3

g(f(-∛3))=g(-3)=(-3)⁶=3⁶=81×9=729

f(g(∛2))-g(f(-∛3))=64-729=-665

4. f, g : R -> R

f(x)=x²

3f(x)+2x-1=0

3x²+2x-1=0

delta=b²-4ac=4+12=16

x1=(-2-4)/2×3=-6/6=-1

x2=(-2+4)/2×3=2/6=1/3

f(2x-3)-f(x)+3=0

(2x-3)³-x³+3=0

(2x-3-x)[(2x-3)²+x(2x-3)+x²]+3=0

(x-3)(4x²-12x+9+2x²-3x+x²)+3=0

(x+3)(7x²-15x+9)+3=0

(x+3)(x²-6x+9+6x²-9x)+3=0

(x+3)[(x-3)²-3x(2x-3)]+3=0

8x³-3×4x²×3+3×2x×3²-27-x³+3=0

8x³-36x²+54-27-x³+3=0

7x³-37x²+30=0